如何解决Matlab错误Too many output arguments.

2025-10-23 16:38:14

1、书上的代码如下：

function [s, phis, ds, dphi, S] = qmin (phi, a, b, delta, epsilon)

s0 = 1; maxj = 20; maxk = 30; big = 1e6; err = 1; k = 1;

S(k) = s0; cond = 0; h = 1; ds = 0.00001;

if (abs (s0) > 1e4), h = abs(s0) * (1e-4); end

while (k < maxk && err > epsilon && cond ~= 5)

f1 = (feval (phi, s0 + ds) - feval(phi, s0 - ds)) / (2 * ds)

if(f1 > 0), h = -abs(h); end

s1 = s0 + h; s2 = s0 + 2 * h; bars = s0;

phi0 = feval(phi, s0); phi1 = feval (phi, s1);

phi2 = feval(phi, s2); barphi = phi0; cond = 0;

j = 0;

while (j < maxj && abs (h) > delta && cond == 0)

if (phi0 <= phi1),

s2 = s1; phi2 = phi1; h = 0.5 * h;

s1 = s0 + h; phi1 = feval (phi, s1);

else if (phi2 < phi1),

s1 = s2; phi1 = phi2; h = 2 * h;

s2 = s0 + 2 * h; phi2 = feval (phi, 2);

else

cond = -1;

end

j = j + 1;

if (abs (h) > big || abs (s0) > big), cond = 5; end

end

if (cond == 5),

bars = s1; barphi = feval (phi, s1);

else

d = 2 * (2 * phi1 - phi0 - phi2);

if (d < 0),

barh = h * (4 * phi1 - 3 * phi0 - phi2)/d;

else

barh = h / 3; cond = 4;

end

bars = s0 + barh; barphi = feval (phi, bars);

h = abs (h); h0 = abs (barh);

h1 = abs (barh - h); h2 = abs (barh - 2 * h);

if (h0 < h), h = h0; end

if (h1 < h), h = h1; end

if (h2 < h), h = h2; end

if(h == 0), h = barh; end

if (h < delta), cond = 1; end

if (abs (h) > big || abs (bars) > big), cond = 5; end

err = abs (phi1 - barphi);

s0 = bars; k = k+1; S(k) = s0;

end

if (cond == 2 && h < delta), cond = 3; end

end

s = s0; phis = feval (phi, s);

ds = h; dphi = err;

end