用C语言编写，求等差数列

1、打开visual C++ 6.0-文件-新建-文件-C++ Source File

2、定义变量：

#include <stdio.h>

void main()

{

    int j, number, n;

3、对数进行穷举：

    for (number = 1; number < 6; number++)                   /*对1到5之间的数进行穷举*/

        for (n = 1; n < 4; n++)                              /*对1到3之间的数进行穷举*/

4、判断是否满足条件：

    if ((4 *number + 6 * n == 26) && (number *(number + n)*(number + 2 * n)*

        (number + 3 * n)) == 880)                        /*判断是否满足题中条件*/

5、输出结果并用循环：

        printf("结果是:\n");

        for (j = 1; j <= 20; j++)

6、输出数列中的20个数：

            printf("%3d", number);

            number += n;

            if (j % 5 == 0)                                  /*每输出5个进行换行*/

                        printf("\n");

7、完整的源代码：

#include <stdio.h>

void main()

{

    int j, number, n;

    for (number = 1; number < 6; number++)                   /*对1到5之间的数进行穷举*/

        for (n = 1; n < 4; n++)                              /*对1到3之间的数进行穷举*/

    if ((4 *number + 6 * n == 26) && (number *(number + n)*(number + 2 * n)*

        (number + 3 * n)) == 880)                        /*判断是否满足题中条件*/

    {

        printf("结果是:\n");

        for (j = 1; j <= 20; j++)

        {

            printf("%3d", number);

            number += n;

            if (j % 5 == 0)                                  /*每输出5个进行换行*/

                        printf("\n");

        }

    }

}