如何搭建struts2项目
1、从网上下载struts2需要的jar包，以下是需要用到的jar包
2、1.在myeclipse中新建web工程，随便起名字，例如我的是叫logintest
3、2.导入需要引用的jar包，在logintest项目上右键->build path->configure bulid path,点击libraries,点击add external jars...,选择你的struts2需要用到的jar包的位置添加进来，点击ok
4、3.在WebRoot下找到web.xml文件进行配置，将下面的代码粘贴过去<?xml version=媪青怍牙"1.0" encoding="UTF-8"?><web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"> <!-- 定义struts2的核心filter即struts2的FilterDispatcher的filter --> <filter> <filter-name>struts2</filter-name><!-- 定义核心filter的名称 --> <filter-class><!-- 定义核心filter的实现类 --> org.apache.struts2.dispatcher.FilterDispatcher </filter-class> </filter> <!-- 核心filter拦截所有请求 即FilterDispatcher用来初始化struts2并且处理所有的web请求--> <filter-mapping> <filter-name>struts2</filter-name> <url-pattern>/*</url-pattern> </filter-mapping></web-app>
5、在src里面新建一个xml文件命名为struts.xml,然后将下面的代码粘贴到此文件中<?xml version="1.0" encoding="UTF-8"?><!DOCTYPE struts PUBLIC "-//Apache Software Foundation//DTD Struts Configuration 2.0//EN" "http://struts.apache.org/dtds/struts-2.0.dtd"><struts> <!-- 若package加上namespace属性，则jsp页面form 的action属性必需加上项目名称的路径--> <package name="struts2" extends="struts-default" namespace="/demo"> <action name="login" class="com.action.LoginAction" > <result>/loginsuccess.jsp</result> </action> </package> </struts>
6、在src中新建一个包，命名为com.action,在此包下新建一个类命名为LoginAction，将下面的代码站提过去package com.action;import com.opensymphony.xwork2.ActionSupport;public class LoginAction extends ActionSupport{ private String username; private String password; public String getUsername() { return username; } public void setUsername(String username) { this.username = username; } public String getPassword() { return password; } public void setPassword(String password) { this.password = password; } public String execute(){ System.out.println("走进action"); return SUCCESS; } public String login(){ return SUCCESS; }}
7、在WebRoot下新建一个jsp，命名为login.jsp，将下面的代码复制过去&盟敢势袂lt;%@ page language=媪青怍牙"java" import="java.util.*" pageEncoding="UTF-8"%><%String path = request.getContextPath();String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";%><!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"><html> <head> <base href="<%=basePath%>"> <title>My JSP 'login.jsp' starting page</title> <meta http-equiv="pragma" content="no-cache"> <meta http-equiv="cache-control" content="no-cache"> <meta http-equiv="expires" content="0"> <meta http-equiv="keywords" content="keyword1,keyword2,keyword3"> <meta http-equiv="description" content="This is my page"> <!-- <link rel="stylesheet" type="text/css" href="styles.css"> --> </head> <body> <form action="/attendance_book/demo/login.action" method="post"> 账号：<input type="text" name="username"/><br/> 密码:<input type="text" name="password"/><br/> <input type="submit" value="确定"> </form> </body></html>
8、在WebRoot下新建一个jsp，命名为loginsuccess.jsp，将下面的代码复制过去<%@ page language="java" import="java.util.*" pageEncoding="UTF-8"%><%String path = request.getContextPath();String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";%><!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"><html> <head> <base href="<%=basePath%>"> <title>My JSP 'loginsuccess.jsp' starting page</title> <meta http-equiv="pragma" content="no-cache"> <meta http-equiv="cache-control" content="no-cache"> <meta http-equiv="expires" content="0"> <meta http-equiv="keywords" content="keyword1,keyword2,keyword3"> <meta http-equiv="description" content="This is my page"> <!-- <link rel="stylesheet" type="text/css" href="styles.css"> --> </head> <body> 用户名：${request.username} 密 码：${requestScope.password} </body></html>
9、将此项目添加到tomcat中，启动tomcat,在地址栏输入地址：http://127.0.0.1:8080/logintest/login.jsp，
10、在此文本框中输入用户名和密码，会跳到下面的页面
