Python 随机获取list列表元素

1、方式一：def choice(self, seq)返回的为单个元素举例：import randomdef get_word(): word_list = ["koby", "James","Rose", "Iverson"] print(random.choice(word_list))if __name__ == '__main__': get_word()返回：随机返回一个值

2、方式二：def choices(self, popu盟敢势袂lation, weights=None, *, cum_weights=None, k=1)返回的为新的元素列表，可以通过k关键字控制新列表元素的个数，默认1个。A举例：import randomdef get_word(): word_list = ["koby", "James","Rose", "Iverson"] # print(random.choice(word_list)) print(random.choices(word_list))if __name__ == '__main__': get_word()返回：随机返回包含一个元素的列表

3、B举例：import randomdef get_word(): word_list = ["koby", "James","Rose", "Iverson"] # 默认k=1，可以取一个元素时，k可省略 print(random.choices(word_list, k=3))if __name__ == '__main__': get_word()返回：随机返回包含多个元素的列表

4、C举例：import randomdef get_word(): word_list = ["koby", "James"稆糨孝汶;,"Rose", "Iverson"] # print(random.choice(word_list)) for i in range(10): print(random.choices(word_list, weights= [5, 2, 1, 0]))if __name__ == '__main__': get_word()返回：随机返回包含多个元素的列表，可控制出现权重的方式；由结果可见，权重高的元素出现比例高。

5、方式三：def sample(self, population, k)返回的为新的元素列表，可以通过k关键字控制新列表元素的个数，默认1个。import randomdef get_word(): word_list = ["koby", "James","Rose", "Iverson"] print(random.sample(word_list, 1))if __name__ == '__main__': get_word()

6、方式四：借用random.randint返回随机值处理返回结果为单个元素import randomdef get_word(): word_list = ["koby", "James","Rose", "Iverson"] print(word_list[random.randint(0, len(word_list))])if __name__ == '__main__': get_word()